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18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100^(@)C is : |
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Answer» 7.60 torr `p^(@)`, vapour PRESSURE of pure WATER at `100^(@)C` `=760` torr `x=((18)/(180))/((18)/(180)+(178*2)/(18))=(0*1)/(0*1+9*9)=(0*1)/(10)` `:.(0*1)/(10)=(760-p)/(760)` Solving `p=752*4` torr. |
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