18 g of glucose (C_(6) H_(12) O_(6)) (molar mass = 180 g mol^(-1)) is – InterviewSolution

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1.	18 g of glucose (C_(6) H_(12) O_(6)) (molar mass = 180 g mol^(-1)) is dissolved in 1 kg of water in a sauce pan . At what temperature will this solution boil ? (Kb for water = 0.52 K kg mol^(-1) , boiling point of water = 373.1 K)
Answer» SOLUTION :`373.202` K

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