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`180ml` of hydrogen diffuses through a porous membrane in 15 minutes while `120 ml` of `SO_(2)` under identical conditions diffused in 20 minutes. What is the molecular mass of the hydrocarbon ?A. 8B. 16C. 24D. 32 |
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Answer» Correct Answer - 2 `(r_(1))/(r_(2))=sqrt((M_(SO_(2)))/(M_("hydrocarbon")))(180//15)/(120//20)=sqrt((64)/(M))` `2=sqrt((64)/(M))=M=16` |
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