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The cirtical constant for water are `374^(@)C` 218 atm and 0.0566 liter `mo1^(-1)` Calculate a,b and `R` . |
Answer» Given `T_(C) = 374^(@) C =374 + 273 = 647K` `P_(C) = 218 atm` `V_(C) = 0.0566 "litre" mo1^(-1)` `b = (V_(C))/(3) = (0.0566)/(3) = 0.0189 "litre" mo1^(-1)` `a =3P_(C) V_(C)^(2) =3 xx 218 xx (0.0566)^(2)` ` =2.095 litre^(2) "atm mo1"^(-2)` `R = (8)/(3) (P_(C)V_(C))/(T_(C)) = (8 xx 218 xx 0.0566)/(3 xx 647)` `0.05086 "litre atm"K^(-1) mo1^(-1)` . |
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