18gm water is added in a 200 gm sample of Oleum labeled as 109%. The n – InterviewSolution

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1.	18gm water is added in a 200 gm sample of Oleum labeled as 109%. The new labelling of the final sample is :
Answer» `106%` `103%` `100%` `0%` Solution :MINIMUM labelling of OLEUM `= 100%` All free `SO_(3)` is exhausted using `18GM` of water and pure `218gm H_(2)SO_(4)` formed.

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