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                                    1g of a gas at 7°C and 2 atmosphere pressureoccupies a volume of 410 mL. Determine themolar mass of the gas.(R - 0.082 litre atmosphere moleK) | 
                            
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Answer»  Mass M: 1 gPressure P = 2 atmVolume V = 410/1000=0.410 LGas Constant R=0.082 L atm K−1mol−1Temperature T= 7°C +273.15 = 280 K Now we know, PV=nRTn = PV/RTn = 2*.410/.082*280n = 10/280 Molar mass = grams /mol= 1/(10/280)= 280/10 = 28 g/mol  | 
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