1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4). The volume of KMnO_(4) needed to convert Fe^(2+) ions to Fe^(3+) ions in 100 mL original solution is:

1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate

1.	1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4). The volume of KMnO_(4) needed to convert Fe^(2+) ions to Fe^(3+) ions in 100 mL original solution is:
Answer» `71 ML` `142 mL` `35.7 mL` `80 mL` Solution :Meq. Of `Fe^(2+)`=Meq. Of `KMnO_(4)` (for `100 mL` solution) `1/56xx1000=0.1xx5xxV` `:. V=35.7 mL`