1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4). The volume of 0.1 M K_(2)Cr_(2)O_(7) used after reducing the solution mixture with Zn+H_(2)SO_(4) is :

1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate

1.	1g pure iron is dissolved in excess of H_(2)SO_(4). The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4). The volume of 0.1 M K_(2)Cr_(2)O_(7) used after reducing the solution mixture with Zn+H_(2)SO_(4) is :
Answer» `4.64 mL` `5.46 mL` `3.46 mL` `2.64 mL` SOLUTION :MEQ. Of `Kr_(2)Cr_(2)O_(7)=Meq. Of Fe^(2+)` [from `Fe+` from `Fe_(2)(SO_(4))_(3)`] `V=4.64 mL`