`1kg` ice at `-10^(@)C` is mixed with `1kg` water at `100^(@)C`. Then – InterviewSolution

InterviewSolution

1.	`1kg` ice at `-10^(@)C` is mixed with `1kg` water at `100^(@)C`. Then final equilirium temperature and mixture content.
Answer» Heat taken by `1kg` Ice = Heat given by `1kg` water `1 xx (1)/(2)xx 10 +1 xx 80 +1 xx T = 1 xx (100 -T)` `85 -100 - 2T rArr 2T = 15` `theta = (15)/(2) = 7.5^(@)C`, water

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