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`1kg` ice at `-10^(@)` is mixed with `1kg` water at `50^(@)C`. The final equilibrium temperature and mixture content. |
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Answer» Heat taken by ice `5= Kcal + 80 Kcal = 85 Kcal` Heat given by water `= 1 xx 1 xx 50 = 50 Kcal` Heat `gt` Heat given so, ice will not complete melt let m g ice melt then `1 xx (1)/(2) xx 10 +80 m = 50` `80 m = 45 rArr m = (45)/(80)` Content of mixture `{:{("water"(1+(45)/(80))kg),("ice"(1-(45)/(80))kg):}}` and temperature is `0^(@)C` |
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