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`1mol` of a mono-atomic gas is subjected to following cyclic process: a. Calculate `T_(1)` and `T_(2)`. b. Calculate `DeltaU,q,` and `W` in calories in each step of cyclic process. |
Answer» (a) At A `PV=nRT` `20xx1=1xx0.0821xxT_(1)` `T_(1)=243.6K` At B: `PV=nRT` `20xx10=1xx0.0821xxT_(2)` `T_(2)=2436.05K` (b) Path AB: isobaric process `(DeltaU=0,q=w)` `w=PDeltaV=20xx9=180` litre-atm `=(180xx101.3)/(4.185)cal` `=4356.9cal` (work in compression is positive) Path BC: Isochoric process w=0 `q_(V)=DeltaU=nC_(V)DeltaT=1xx(3)/(2)Rxx(2436-243.6)` `=(3)/(2)xx2xx2192.4=6577.2cal` It is cooling process, `q_(V)=-6577.2cal` Path CA: It is isothermal compression `DeltaV_(0)` `q=w=2.303nRtlog(V_(2))/(V_(1))` `q=w=2.303xx1xx2xxlog((10)/(1))=1122.02cal` |
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