1.

1muC charge is placed on each vertex of a regular hexagon. Side of hexagon is 1 m, then electric field at its centre is.......

Answer»

`5/6 XX 10^(-6)k`
`5 xx 10^(-6)k`
`6/5 xx 10^(-6)`k
`10^(-6)`k

Solution :Electric field at center of hexagon.
`E =(kQ)/r^(2) = k xx (1 xx 10^(-6))/(1)^(2)`
`therefore E =10^(-6) K`


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