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`1xx10^(3)m" solution of Pt "(NH_(3))_(4)Cl_(4) " in "H_(2)O` shows depression in freezing point by `0.0054^(@)C`. The structure of the compound will be `("given "K_(f)(H_(2)O)=1.860km^(-1))`A. `[Pt(NH_(3))_(4)]Cl_(4)`B. `[Pt(NH_(3))_(3)Cl]Cl_(3)`C. `[Pt(NH_(3))_(2)Cl_(2)]Cl_(2)`D. `[Pt(NH_(3))Cl_(3)]Cl` |
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Answer» Correct Answer - C `DeltaT_(f)=iK_(f)m` `0.0054=ixx1.86xx0.001` `i=(5.4)/(1.86)=2.90~=3` `So,[Pt(NH_(3))_(2)Cl_(2)]Cl_(2) " is the structure of the compound"` `[Pt(NH_(3))_(2)Cl_(2)]Cl_(2)hArr[Pt(NH_(3))_(2)Cl_(2)]^(o+)+2Cl^(Θ)` |
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