2-1 0 130.y=f(x) = 11-1.Domain r=R {()}Range f R (0)2OBJECTIVE QUESTIO

1.	2-1 0 130.y=f(x) = 11-1.Domain r=R {()}Range f R (0)2OBJECTIVE QUESTIONSSets, Rclations & Functions. Twofinite sets A and B have m and n clements respectively. Inumber of relation from A to B is 64 then the possible values ccan bc(a) 1 and 5(c) 2 and 3IfA r: 3n+ 1,2sn < 53, then number of subsets of A(a) 4(c) 8Which of the following is a null sct?(b) 2 and 4(d) 1 and 4(b) 16(d) nonc of these(b) x: x2+2x +1 0,x R(d) none of these(c) {x:İx1<1.xc. N(a) 3 N(c) N(b)7N(d)21 N
Answer» 1) no of. relation between 2 sets having elements as m and n is given by 2^(mn)so, here no. of relationship = 64 possible value is 2^(23) = 2^6 = 64... option C. 2) Given x = 3n+1 and. 2 ≤ n < 5. so, the set x ={ 7,10,13} and no of subset is 2ⁿ , where n is the no. of elements in the set =2³ = 8 .... option C 3) option C . because there the relation is \|x\| <1 ,but x belongs natural no. but natural no. can't be less that 1.so, it is a null set 4) the set describes the values , which are divisible by 3 and 7... up till N. so the intersection between these two sets will br would be multiple of 37 only = 21N.option D.

2-1 0 130.y=f(x) = 11-1.Domain r=R {()}Range f R (0)2OBJECTIVE QUESTIONSSets, Rclations & Functions. Twofinite sets A and B have m and n clements respectively. Inumber of relation from A to B is 64 then the possible values ccan bc(a) 1 and 5(c) 2 and 3IfA r: 3n+ 1,2sn < 53, then number of subsets of A(a) 4(c) 8Which of the following is a null sct?(b) 2 and 4(d) 1 and 4(b) 16(d) nonc of these(b) x: x2+2x +1 0,x R(d) none of these(c) {x:İx1<1.xc. N(a) 3 N(c) N(b)7N(d)21 N

Answer»

1) no of. relation between 2 sets having elements as m and n is given by 2^(mn)so, here no. of relationship = 64 possible value is 2^(2*3) = 2^6 = 64... option C.

2) Given x = 3n+1 and. 2 ≤ n < 5. so, the set x ={ 7,10,13} and no of subset is 2ⁿ , where n is the no. of elements in the set =2³ = 8 .... option C

3) option C . because there the relation is |x| <1 ,but x belongs natural no. but natural no. can't be less that 1.so, it is a null set

4) the set describes the values , which are divisible by 3 and 7... up till N.

so the intersection between these two sets will br would be multiple of 3*7 only = 21N.option D.

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