(2) 250ml, round bottom flask containing air washeated from 27°C to 4

1.	(2) 250ml, round bottom flask containing air washeated from 27°C to 477°C calculate whatfraction of the air is left behind in the flask
Answer» Let the volume of the round bottomed flask beV. Then, the volume of air inside the flask at 27° C isV. Now, V1=V T1= 27°C = 300 K V2=? T2= 477° C = 750 K According to Charles’s law, V1/T1= V2/T2 => V2=V1T2/T1 =V(750/300) = 2.5V Therefore, volume of air expelled out = 2.5V–V= 1.5V Hence, fraction of air expelled out = (1.5V)/2.5V) = 3/5 Fraction remaining in the flask = 2/5

(2) 250ml, round bottom flask containing air washeated from 27°C to 477°C calculate whatfraction of the air is left behind in the flask

Answer»

Let the volume of the round bottomed flask beV.

Then, the volume of air inside the flask at 27° C isV.

Now,

V1=V

T1= 27°C = 300 K

V2=?

T2= 477° C = 750 K

According to Charles’s law,

V1/T1= V2/T2

=> V2=V1T2/T1

=V(750/300)

= 2.5V

Therefore, volume of air expelled out = 2.5V–V= 1.5V

Hence, fraction of air expelled out = (1.5V)/2.5V) = 3/5

Fraction remaining in the flask = 2/5