2+3+4+⋯+(n-1)= (a) n-2 (b) n (n+1)/2(c) (n+1) (n-2) / 2(d) n (n-1)

1.	2+3+4+⋯+(n-1)= (a) n-2 (b) n (n+1)/2(c) (n+1) (n-2) / 2(d) n (n-1) / 2
Answer» i THINK MERE tykke KE hisaab SE PART d

2+3+4+⋯+(n-1)= (a) n-2 (b) n (n+1)/2(c) (n+1) (n-2) / 2(d) n (n-1) / 2

Answer»

i THINK MERE tykke KE hisaab SE PART d

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2+3+4+⋯+(n-1)= (a) n-2 (b) n (n+1)/2(c) (n+1) (n-2) / 2(d) n (n-1) / 2​

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2+3+4+⋯+(n-1)= (a) n-2 (b) n (n+1)/2(c) (n+1) (n-2) / 2(d) n (n-1) / 2