2.5g sample of copper is dissolved in excess of H_(2)SO_(4) to prepare100 mL of 0.02 MCuSO_(4) (aq) . 10 mL of 0.02 M solution of CuSO_(4) (aq) is mixed with excess of Kl to show the following changes CuSO_(4) + 2Kl to K_(2)SO_(4) + Cu l_(2) 2Cu l_(2) to Cu_(2)l_(2) + l_(2) The liberated iodine is titrated with hypo (na_(2)S_(2)O_(3)) andrequires V mL of 0.1 M hypo solution for its complete reduction . The amount of l_(2) liberated in the reaction of 10 mL of 0.02 M solution with Kl (excess ) is :

2.5g sample of copper is dissolved in excess of H_(2)SO_(4) to prepare

1.	2.5g sample of copper is dissolved in excess of H_(2)SO_(4) to prepare100 mL of 0.02 MCuSO_(4) (aq) . 10 mL of 0.02 M solution of CuSO_(4) (aq) is mixed with excess of Kl to show the following changes CuSO_(4) + 2Kl to K_(2)SO_(4) + Cu l_(2) 2Cu l_(2) to Cu_(2)l_(2) + l_(2) The liberated iodine is titrated with hypo (na_(2)S_(2)O_(3)) andrequires V mL of 0.1 M hypo solution for its complete reduction . The amount of l_(2) liberated in the reaction of 10 mL of 0.02 M solution with Kl (excess ) is :
Answer» `0.051` G `0.0254` g `0.102` g `0.204` g SOLUTION :N/A