1.

2.8 g of N_(2) , 0.40 g of H_(2) and 6.4g of O_(2) are placed in a container of 1.0 L capacity at 27^(@)C. The total pressure in the container is :

Answer»

6.12 ATM
12.3 atm
1.23atm
24.6 atm

Solution :Total moles `= ( 2.8 ) /( 28) + ( 0.4)/( 2) + ( 6.4)/( 32) = 0.5 `
`p = ( N RT )/( V )`
or `p = ( 0.5 xx 0.082 xx 300)/( 1)`
`= 12.3 atm`


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