2.8 xx 10^(-2) kgofnitrogen isexpanded isothermallyandreversiblyat 300 kfrom15.15 xx 10^(5) Nm^(-2)when theworkdone isfoundto be -17. 33 kJ.Findthe finalpressure .

2.8 xx 10^(-2) kgofnitrogen isexpanded isothermallyandreversiblyat 300

1.	2.8 xx 10^(-2) kgofnitrogen isexpanded isothermallyandreversiblyat 300 kfrom15.15 xx 10^(5) Nm^(-2)when theworkdone isfoundto be -17. 33 kJ.Findthe finalpressure .
Answer» <P> Solution :Given :MASS ofnitrogen`= W=2.8 xx 10^(-2)kg` Temperature= T =300 K Workobtainedin expansion`=W_(max)=- 17 .33 kJ=-17330 J` Initialpressure`=P_(1)= 15. 15 xx 10^(5) NM^(-2)= 1.515 xx 10^(6)Nm^(-2)` Molar mass ofnitrogen`(N_(2))= M_(N_(2)) = 28xx 10^(-3)kg mol^(-1)` Finalpressure `= P_(2) = ?` Numberof MOLESOF `N_(2)= n. (W)/(M_(N_(2)))= (2.8 xx 10^(-2))/(28xx 10^(-3)) = 1 mol` `W_(max)= -2.303xx nRTlog _(10).(P_(1))/(P_(2))` `17330 = 2.303xx 1 xx 8.314xx 300xx log _(10). (1.515 xx 10^(6))/(P_(2))` `:. (17330)/(2.303 xx 1xx 8.314 xx 300)= [ log_(10) 1.515 xx 10^(6) - log_(10) P_(2)]` `3.017 =6 . 1804 -log _(10) P_(2)` `:. log_(10) P_(2) = 6.1804- 3.017 =3 . 1634` `:. P_(2)= `Antilog3.1634 `=1456.8 Nm^(-2)`