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2 cos theta + 2√2 =3 sec theta |
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Answer» cosθ+2 2 =3secθ2cos 2 θ+2 2 cosθ= 23 LET cos 2 θ=ycosθ= 2 −1+2 y 2 + 2 y= 23 =0⇒ 2 −1+2 , 2 −1−2 y= 2− 2 ± 2−4( 43 ) cosθ= 2 1 , 2 −3 = 2− 2 ± 2+6 = 2− 2 ±2 2 |
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