Saved Bookmarks
| 1. |
(2-cos theta) whole square is equals to |
Answer» LHS=(1−sinθ+cosθ)2
LHS=1+sin2θ+cos2θ−2sinθ+2cosθ−2sinθcosθLHS=2−2sinθ+2cosθ−2sinθcosθLHS=2(1−sinθ)+2cosθ(1−sinθ)LHS=2(1−sinθ)(1+cosθ)=RHS❤CrazyGirl here❤ |
|