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$$2\frac{1}{9} \times 1\frac{2}{19} \div 2\frac{1}{3} = ? - 1\frac{1}{2}$$1). $$3\frac{1}{2}$$2). $$1\frac{1}{4}$$3). $$2\frac{1}{2}$$4). $$2\frac{1}{4}$$ |
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Answer» Solution Let the unknown be $x$. |
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