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2. In a AABC, if ZA=72º and ZB=63° find ZC. |
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Answer» Angle A + angleB+ angle C =180°72+63+ angle C=180°angle C =180°(72+63)°angle C =180°-135°Angle C =145° sorry not 145 only 45 45°by asp of triangle Angle A + angle B + angle C = 180°72° + 63° + c = 180°c = 45° angle c is 45 degree Angle A +Angle B+Angle c=180 72+63+angle C=180 °angle C=180° A+B+C=180°72+63+c=180°C=180°-135°C = 45° A/Q angle A + angle B + angle C = 180° [ property of triangle ]=>72° + 63 ° + angle C = 180°=>135° + angle C = 180°=> angle C = 180° - 135°=> angle C = 45° ans 45° with the correct answer sum of 4terms of an AP IS 20and it's sum of it's squares are 120 |
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