InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
2. In a AABC, if ZA=72º and ZB=63° find ZC. |
| Answer» <p>Angle A + angleB+ angle C =180°72+63+ angle C=180°angle C =180°(72+63)°angle C =180°-135°Angle C =145°</p> <p>sorry not 145 only 45</p> <p>45°by asp of triangle</p> <p>Angle A + angle B + angle C = 180°72° + 63° + c = 180°c = 45°</p> <p>angle c is 45 degree</p> <p>Angle A +Angle B+Angle c=180 72+63+angle C=180 °angle C=180°</p> <p>A+B+C=180°72+63+c=180°C=180°-135°C = 45°</p> <p>A/Q angle A + angle B + angle C = 180° [ property of triangle ]=>72° + 63 ° + angle C = 180°=>135° + angle C = 180°=> angle C = 180° - 135°=> angle C = 45° ans</p> <p>45° with the correct answer</p> <p>sum of 4terms of an AP IS 20and it's sum of it's squares are 120</p> | |