1.

2. In parallelogram PQRS, angle Q = (4x - 5)º andS = (3x + 10)". Calculate : angle Q and angle R. 3. In rhombus ABCD :(i) if angleA = 74°; find angle B and angle C(ii) if AD = 7.5 cm; find BC and CD.4. In square PQRS :(i) if PQ = 3x - 7 and QR = x + 3; find PS.(ii) if PR = 5x and QS = 9x - 8. Find QS.​

Answer»

Answer:

Step-by-step explanation:

THE 2 ONE IS THE PIC

3 .

GIVEN Information:-

In Rhombus ABCD, angle A = 74°

AD = 7.5 cm

To Find:-

Angle B and C Measurement.

Length of BC and CD.

_______________________...

1. Angle of B and C measurement:-

Here, Angle A = 74°

Hence, Angle B = 180° - Angle A

= 180° - 74°

= 106° (Angle B value)

Therefore, measurement of angle C:

= 180° - Angle B

= 180° - 106°

= 74° (Angle C value)

Hence,

Angle B = 106°

Angle C = 74°

______________________...

2. Length of BC and CD:-

Here, AD = 7.5 cm

As we know, in a Rhombus,

P=4S

(where P means Perimeter and S stands for sides)

Henceforth, BC = 7.5 cm

and also CD = 7.5 cm

REQUIRED ANSWER:-

Angle of B = 106 and of C = 74

.Length of BC and CD is 7.5 cm

4.

As it is a Square :

So,

*All the sides are equal ...

So,

3x-7=x+3

3x-x=7+3

2x=10

x=10/2

=>x = 5

Substituting:

x+3 = 5+3 = 8

PS = 8

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We know that the diagonals of a square are equal

Thus,  

PR = QS  

5x = 9X - 8

4x = 8

x = 2.

Now,

QS = 9x - 8 = 18 - 8 = 10.

Thus,  

QS = 10.

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I HOPE U UNDERSTAND

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SARANGAE



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