2. In the adjoining figure, the diagonals AC and BD of parallelogram ABCD intersect at 0. If angleOBC = 36°, angleODC = 28° and angleAOD = 64°; find the measure of (i) angleOAD (ii) angleOCD.

2. In the adjoining figure, the diagonals AC and BD of parallelogram A

1.	2. In the adjoining figure, the diagonals AC and BD of parallelogram ABCD intersect at 0. If angleOBC = 36°, angleODC = 28° and angleAOD = 64°; find the measure of (i) angleOAD (ii) angleOCD.
Answer» OAD= 58degreeStep-by-step explanation:SIDES OF A PARALLELOGRAM ARE PARALLEl OA=OD(DIAGONAL OF A PARALLELOGRAM BISECT EACH OTHER) THUS ANGLE OAD=ODA (ANGLES OPP. TO EQUAL SIDES ) so angle OAD + angle DOA+ ANGLE ODA =180 angle 2OAD+ 64°=180° 2OAD=180-64 2OAD=116 OAD,=116/2 OAD =58° ¡¡ OC=OD ( DIAGONAL OF A PARALLELOGRAM BISECT EACH OTHER) THUS ANGLE ODC=ANGLE OCD=28°(ANGLES OPP. TO EQUAL SIDES)