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2 % items in a lot are defective. What is the probability that an item randomly selected from this lot is non-defective? |
Answer» A = Event that an item is defective ∴ P(A) = 2 % = \(\frac{2}{100 }\)= 0.02 A’ = Event that an item is non-defective ∴ P(A’) = 1 – P(A) = 1 – 0.02 = 0.98 |
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