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2. Joseph jogs from one end A to the other end B of a strug300 m road in 2 minutes 30 seconds and then turns arounand jogs 100 m back to point in another 1 minute WhatanJoseph's average speeds and velocities in jogging (a) from AB and (b) from A to C? |
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Answer» Step-by-step explanation: Velocity = dispacement / time Speed = DISTANCE / time a) when he jogs from A to B on a straight road, DISPLACEMENT = distance = 300m time = 2 MINUTES 30 seconds = 150 s velocity = 300/150 = 2 m/s speed = 300/150 = 2m/s b)when he jogs from A to B and turns back to C, displacement = 300-100 = 200m distance = 300+100 = 400m time = 3 minute 30 second = 210 s velocity = 200/210 = 20/21 m/s speed = 400/210 = 40/21 m/s |
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