1.

2 mole of ideal momoatmic gas was subjected toreversibleadiabaticcompression from initianl state of P= 1 andT = 300 Ktill the pressrue is 4sqrt(2) atm and temperature is TK . The gas is then subjected to reversible isothermal expansion atT K tilltheinternalpressureis one atm . The gas is nowisobarically cooled to attaininitialstate. Find W_(Net) ( in calorie) forwhole process . [Use In2=0.7]

Answer»


Solution :`T_(2)= T_(1)(P_(1)/(P_(2)))^(((1-gamma)/(gamma))`
` = 600 K`
`W_(I)= W_("rev")= nC_(V)[T_(2)- T_(1)] = 2 xx (3)/(2) R xx 300`
`= 900 R`
`W_(II)= - 2.303 nRT LOG .(P_(1))/(P_(2)) = - 2xx R xx 600 In ((4sqrt(2))/(1))`
`W_(III) = - PDeltaV = - nRT = - 1200R xx (5)/(2) xx 0.7 = - 2100 R`
`W_("Total") = 900 R - 2100 R + 600 R`
` = - 600 R = - 1200 CAL`


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