1.

2 moles of helium gas expanded isothermally and irreversibly at 27^(@)C from volume 1 dm^(3) to 1 m^(3) at constant pressure of 100 kPa. Calculate the work done.

Answer»

99900 kJ
99900 J
34464.65 kJ
34464.65 J

Solution :`W=-pDeltaV`
Given, `p=100" kPa"=10^(5)Pa`,
`V_(1)=1dm^(3)=10^(-3)m^(3),V_(2)=1m^(3)`
`W=10^(5)xx(1-10^(-3))J=99900J`


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