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`2` moles of ideal gas is expanded isothermally & reversibly from `1` litre to `10` litre. Find the enthalpy changes in `KJ mol^(-1)`. |
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Answer» Correct Answer - A ` because H=E+PV` and `Delta H=Delta E+PDelta V` `:. Delta H=Delta E +nRDelta T` For isotermal and reversible process `Delta T=0` `:. Delta H=Delta E+0` ,brgt `because Delta E=0` `because Delta H` is also equal to zero. |
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