1.

2 moles of N_(2) O_(4 (g)) is kept in a closed container at 298 K and under 1 atm pressure . It is heated to 596 K when 20% by mass of N_(2) O_(4 (g)) decomposes to NO_(2) . The resulting pressure is

Answer»

2.4 atm
1.2 atm
4.8 atm
2.8 atm

SOLUTION :`{:(, 2 N_(2) O_(4) to 4 NO_(2)), (" Initially " ,2 ""0) , ("At 596 K" , 2p ""4p), ("Finally" , 2-2p ""4p):}`
As given , `2p = (20 xx 2)/(100)`
2p = 0.4
`THEREFORE p = 0.2` atm
Resulting pressure (P) = 2- 2p + 4p
P = 2 +2 p
P = 2 + 2 (0.2) = 2.4 atm


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