2 moles of Ne gas and 5 moles of He gas, both samples having average velocity 7xx10^2 m//s, are mixed.Find the average translational kinetic energy per mole of the given gas mixture (in joules).Report your answer as 'X' where X=(Average translational KE in joules)xx0.002.The reported answer should be upto nearest integer.

2 moles of Ne gas and 5 moles of He gas, both samples having average v

1.	2 moles of Ne gas and 5 moles of He gas, both samples having average velocity 7xx10^2 m//s, are mixed.Find the average translational kinetic energy per mole of the given gas mixture (in joules).Report your answer as 'X' where X=(Average translational KE in joules)xx0.002.The reported answer should be upto nearest integer.
Answer» SOLUTION :Average Translational kinetic energy (per mole of gas)`=3/2RT=(3M)/2xx(RT)/M=(3piM)/16xx(8RT)/(piM)` `=(3piM)/16xx(sqrt((8RT)/(piM)))^2=(3piM)/16xx(v_(AV))^2` `:.` For one mole of gas MIXTURE, Average translational kinetic energy `=(3piM_("mix"))/16xx(v_(av))^2` `=3/16xx22/7xx[((2xx20+5xx4)//7)/1000]xx(7xx10^2)^2[because M_(mix) " is in" kg//"mole"]` =2475 Joules. Reported ANSWER=`2475xx0.002=4.75~~5`