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2. The length of a hall is 8 m and its width is 13.5 m. Find the least number of square tiles each of 25 cm recuired to cover the floor [ [3]​

Answer» <html><body><p>Length of <a href="https://interviewquestions.tuteehub.com/tag/hall-1015083" style="font-weight:bold;" target="_blank" title="Click to know more about HALL">HALL</a> =18m=1800cmBreadth of hall =13.5m=1350cmWidth of margin =<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.5m=150cmNow, <a href="https://interviewquestions.tuteehub.com/tag/efgh-445383" style="font-weight:bold;" target="_blank" title="Click to know more about EFGH">EFGH</a> is the required <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> of hall flow to be filled.Now, length of floor =1800−(2×150)=1500cmBreadth of floor =1350−(2×150)=1050cm∴  Area EFGH=1500×1050=1575000cm2Area of 1 square tile =25×25=625cm2Number of tiles =Areaof1tileAreaEFGH=6251575000=2520</p></body></html>


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