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2. The triangular side walls of a flyover have been used for advertisements. The si the walls are 122 m, 22 m and 120 miee Fig. 12.9). The advertisements yeearning of 5000 per m per year. A company hired one of its walls for 3 monthsmuch rent did it pay? |
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Answer» The company had to pay RS 1650000.Step-by-step EXPLANATION:Area of triangle=√(s(s-a)(s-b)(s-c))Here, s is semi-perimeter,and a,b,c are the side of the triangle.so, a=122m b=22m c=120ms=(a+b+c)/2 =(122+22+120)/2 =132mArea of triangle=√(s(s-a)(s-b)(s-c))putting a=122m b=22m c=120m and s=132mArea =√{132(132-122)(132-22)(132-120)}m^2 =√{132*10*110*12}m^2 =1320m^2Rent of 1 m^2 area par year = 5000Rent of 1 m^2 area par month = 5000/12Rent of 1 m^2 area par 3month = (5000/12)*3Rent of 1320 m^2 area par 3month = {(5000/12)*3}*1320 =1250*1320 =1650000Hope this will help you. |
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