2(x+1)^2-5(x+1)=12 ,solve using factorization method.

1.	2(x+1)^2-5(x+1)=12 ,solve using factorization method.
Answer» Answer: x1 = 3, x2 = -5/2 Step-by-step explanation: 2(x+1)^2-5(x+1)=12 <=> 2(x^2 + 2x + 1) - 5x - 5 - 12 = 0 <=> 2x^2 + 4x + 2 - 5x - 5 - 12 = 0 <=> 2x^2 - x - 15 = 0 Denta = (-1)^2 - 4.2.(-15) = 121 => sqrt (denta) = 11 => x1 = [- (-1) + 11 ]/ 4 = 3 x2 = [- (-1) - 11 ]/ 4 = -5/2

Answer»

Answer:

x1 = 3, x2 = -5/2

Step-by-step explanation:

2(x+1)^2-5(x+1)=12

<=> 2(x^2 + 2x + 1) - 5x - 5 - 12 = 0

<=> 2x^2 + 4x + 2 - 5x - 5 - 12 = 0

<=> 2x^2 - x - 15 = 0

Denta = (-1)^2 - 4.2.(-15) = 121 => sqrt (denta) = 11

=> x1 = [- (-1) + 11 ]/ 4 = 3

x2 = [- (-1) - 11 ]/ 4 = -5/2

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2(x+1)^2-5(x+1)=12 ,solve using factorization method.

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