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(2^x+y,2^x-y)= (16,1) |
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Answer» x=2 and y=2Step-by-step explanation:2^x+y=16 2^x+y=2^4x+y=42^x-y=1 2^x-y=2^0x-y=0 x=ySubstitution method we get x=2 and y=2Please FRIEND Subscribe & SUPPORT My Channel: HTTPS://www.youtube.com/channel/UCVtK9k5zz-pgwX5Ah-wYiCQ |
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