1.

20% aqueous FeCl_(3) solution has density of 1.1 gm/mL then molar concentration of this solution is ……….

Answer»

`0.028`
`1.357`
`0.163`
`1.47`

Solution :`20% FeCl_(3)` solution MEANS 20 gm `FeCl_(3)` is present in 100 gm of solution.
`therefore` VOLUME of 100 gm solution `= (100)/(1.1)=90.91` mL
Moles of 20 gm `FeCl_(3)` solution `= (20)/(162)=0.1234` mol
So, molar concentration solution
`= (0.1234xx1000)/(90.91)=1.357 M`


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