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20 find the value of x3 +y3-12xy+64when x+y=-4 |
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Answer» Answer: x³ + y³ - 12xy + 64 x³ + y³ + 4³ - 3(4XY) (64 = 4³) (x + y + 4)(x² + y² + 4² - XY - 4y - 4x) x + y = - 4 (- 4 + 4) * (x² + y² + 4² - xy - 4y - 4x) 0 * (x² + y² + 4² - xy - 4y - 4x) = 0 Step-by-step EXPLANATION: |
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