1.

20 g of a non-volatile solute is added to 500 g of solvent. Freezing point of solvent = 5.48^(@)C and solution = 4.47^(@)C. K_(f)=1.93^(@)//m. Molecular mas of the solute is

Answer»

`72.2`
`76.4`
`73.2`
`70.6`

Solution :`Delta T_(f)=5.48-4.47=1.01`
`Delta T_(f)=K_(f)XX m`
`RARR 1.01=1.93xx(20)/(M)xx(1000)/(500)rArr M=76.4`.


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