1.

20 gm sample containing Mg. is treated with excess of 2M HCl. As a result 11.2 litre of H_(2) gas at NTP was evolved. Find % purity of Mg in sample

Answer»

0.6
0.3
0.75
0.72

Solution :`Mg+2HClrarrMgCl_(2)+H_(2)`
`n_(Mg)=n_(H_(2))=(11.2)/(22.4)=(1)/(2)`
`w_(Mg)=12gm`
`% "purity"=(12)/(20)xx100=60`


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