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20 J work is required to stretch a spring through 0.1m. Find the force constant of the spring. If the spring is further stretched through 0.1 m, calculate work done. |
Answer» P.E. of spring when stretched through a distance 01m, U = W.D = \(\frac{1}{2}\)Kx2 = 20J K = 4000 N/m when spring is further stretched through 01m, then P.E. will be : U' = \(\frac{1}{2}\) K(0.2)2 = 80J ∴ W.D = U' -U = 80-20 = 60J. |
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