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`20 mL` of `0.2 M Al_(2) (SO_(4))_(3)` is mixed with `20 mL` of `0.6 M BaCl_(2)`. Calculate the concentration of each ion in solution.A. `0.6N, 0.6 N`B. `0.2 N, 0.6 N`C. `0.6 N, 0.2 N`D. `0.2N, 0.2 N` |
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Answer» Correct Answer - A `{:(,Al_(2)(SO_(4))_(3)+,BaCl_(2)rarr,BaSO_(4)darr+,AlCl_(3)),(Meq.at,20xx0.2xx6,20xx0.6xx2,0,0),(t=0,=24,=24,,),("Meq.after reaction",0,0,24,24):}` , `therefore [Al^(3+)]=(24)/(40)=0.6N` `[Cl^(-)]=(24)/(40)=0.6N` |
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