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20 ml of 0.5 N HCl and 35 ml of 0.1 N NaOHare mixed. The resulting solution will |
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Answer» be neutral `0.5 N implies` 1000 ml 0.5 mole HC L is present in`20ml=(20xx0.5)/(1000)=1.0xx10^(-2)` (II) 35 ml of 0.J N NaOH 0.1 N implies 1000 ml of 0.1 mole of NaOH `implies35ml=(35xx0.1)/(1000)=0.35xx10^(-2)` Total `= 20 + 35 = 55 ml` ` implies (1.0 - 0.35)10^(-2) = 0.65 xx 10^(-2) mole HCI` `HCI = H^(+) + CI^(-)` `implies[HCI] = [H\^(+)] + [CH^(-)]` 55 ml contains `0.65 xx 10^(-2)` mole of `H^(+)` ions `1000ML-(0.65xx10^(-2)xx10^(3))/(55)=(6.5)/(55)` `pH=-log[H^(+)]=-log(6.5//55)` `=log55-log6.5=0.92` Due to acidic nature of solution the colour of phenolphthalein becomes pink. |
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