20 " mL of " a gasous bydrocarbon (A) was exploded with excess of `O_2` in an eudiometer tube. On cooling, the volume was reduced by 50 mL. On further treatment with KOH, there was further contraction of 40 mL. The molecular formula of the hydrocarbon A is (a). `C_2H_6` (b). `C_2H_4` ` C_3H_6` (d). `C_3H_8`

20 " mL of " a gasous bydrocarbon (A) was exploded with excess of `O_2

1.	20 " mL of " a gasous bydrocarbon (A) was exploded with excess of `O_2` in an eudiometer tube. On cooling, the volume was reduced by 50 mL. On further treatment with KOH, there was further contraction of 40 mL. The molecular formula of the hydrocarbon A is (a). `C_2H_6` (b). `C_2H_4` ` C_3H_6` (d). `C_3H_8`
Answer» `C_(x)H_(y)(g)+(x+(y)/(4))O_2(g)toxCO_2(g)+(y)/(2)H_2O(l)` `CO_2` is absorbed in KOH. `therefore20x=40impliesx=2` `20mL+20(2+(y)/(4))=40+50` `20+40+(20y)/(4)=90` `5y=90-60=30` `y=6` Formula of the compound is `C_2H_6`.

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