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20 ml of a solution of a weak monobasic acid neutralizes 22.18 ml of solution of NaOH and 20 ml of N/10 HCl neutralizes 21.5 ml of the same NaoH solution. The normality for the acid is nearly |
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Answer» 10 N `N_(1)xx10=N_(2)xx22.18` `N_(1)=(N_(2)xx22.18)/(20)` NAOH solution=HCl solution `N_(2)xx21.5=(1)/(10)xx20` `N_(2)=(20)/(10xx21.5)` By EQ. (i) and (ii) `N_(1)=(20xx22.18)/(20xx10xx21.5)=(22.18)/(215)=0.1N`. |
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