InterviewSolution
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InterviewSolution
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20 " mL of " `(M)/(60)` `KBrO_3` was reacted with a sample of `SeO_(3)^(2-)` 20 The `Br_(2)` thus evolved was removed and the excess of `NaAsO_(2)` The reaction involved are `SeO_(3)^(2-)+BrO_(3)^(ɵ)+H^(o+)toSeO_(4)^(2-)+Br_(2)+H_(2)O` .. (i) `BrO_(3)^(ɵ)+ASO_(2)^(ɵ)+H_(2)OtoBr^(ɵ)+AsO_(4)^(3-)+H^(o+)` ..(ii) `[Mw(SeO_(3)^(2-))=79+48=127gmol^(-1)]` Q. Amount of `SeO_(3)^(2-)` in mg isA. 19.4 mgB. 194 mgC. 970 mgD. 97 mg |
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Answer» Correct Answer - D `m" Eq of "SeO_(3)^(2-)=(55)/(36)` Weight of `SeO_(3)^(2-)=mEqxx10^(-3)xxEw` `(Ew of SeO_(3)^(2-)=(127)/(2))(n=2)` `=(55)/(36)xx10^(-3)xx(127)/(2)g` `=0.097g=97g` |
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