1.

20 mL of methane are burnt with 50 mL of oxygen, the volume of the gas left after cooling to room temperature will be

Answer»

80 mL
60 mL
30 mL
20 mL

Solution :`underset(20 mL)underset(1 vol) (CH_(4)) + underset(40 mL)underset(2 vol)(2O_(2)) to underset(20 mL)underset(1 vol) (CO_(2)) + underset(vol.)underset("NEGLIGIBLE")(2 H_2O)`
VOLUME of `CO_2` formed = 20 mL
Volume of `O_2` USED = 40 mL .
`therefore` Volume of `O_2` left unused = 50 - 40 = 10 mL
Volume of GAS left after cooling = volume of `CO_2` formed + volume of `O_2` left unused = 20 + 10 = 30 mL


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