InterviewSolution
Saved Bookmarks
| 1. |
200 kg of water is heated from `20^(@)C` to `100^(@)C`. If specifice heat of water is `4.2xx10^(3)Jkg^(-1)0C^(-1)`, calculate the increase in the mass of water. |
|
Answer» Here, `m=200kg,` `DeltaT=(100-20)^(@)C=80^(@)C` `s=4.2xx10^(3)Jkg^(-1).^(@)C^(-1)` Heat Energy absorbes, `E=smDeltaT` `=(4.2xx10^(13))xx200xx80J` `E=6.72xx10^(7)J` Increase in mass of water, `m=(E)/(C^(2))=(6.72xx10^(7))/((3xx10^(8))^(2))` `m=7.46xx10^(-10)kg` |
|