1.

200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be 2.57 xx 10^(-3) bar. The molar mass of protein will be (R = 0.083 L bar mol^(-1)K^(-1))

Answer»

51022 g `mol^(-1)`
122044 g `mol^(-1)`
31011 g `mol^(-1)`
61038 g `mol^(-1)`

SOLUTION :According to Van't Hoff equation
`M_(B)=(W_(B)xxRxxT)/(pixxV)`
`=((1.26g)xx(0.083"L bar"mol^(-1)K^(-1))xx(300K))/((2.57xx10^(-3)"bar")xx(0.2 L))`
`=61038 g mol^(-1)`


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