200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`A. `61038 g mol^(–1)`B. `51022 g mol^(–1)`C. `122044 g mol^(–1)`D. `31011 g mol^(–1)`

200 mL of an aqueous solution of a protein contains its 1.26g. The osm

1.	200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`A. `61038 g mol^(–1)`B. `51022 g mol^(–1)`C. `122044 g mol^(–1)`D. `31011 g mol^(–1)`
Answer» Correct Answer - A `piv=w/mRT` `2.5xx10^-3xx200/1000=1.26/mxx0.083xx300` m=61038 gm `mol^-1`

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